Question

3.
A 15 m long ladder reached a window 12 m high
from the ground on placing it against a wall at a
distance a. Find the distance of the foot of the
ladder from the wall.​

Answer 1

Step-by-step explanation:

Let AC be the ladder and A be the window.

Given: AC=15m, AB=12m, CB=am

In right angled triangle ACB,

(Hypotenuse) 2

=(Base) 2

+[Perpendicular) 2

[By Pythagoras theorem]

⇒(AC) 2=(CB) 2+(AB) 2

⇒(15) 2

=(a) 2

+(12) 2

⇒225=a 2

+144

⇒a =2

=225−144=81

⇒a= 81

=9cm

Thus, the distance of the foot of the ladder from the wall is 9m.

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