Question

3(a - 2)² + 6(a-2). factorise it​

Answer 1

Answer:

3a(a-2)

Step-by-step explanation:

=3× [a²+4-2×a×2] + 6a- 12

=3[a²+4-4a] + 6a-12

=3a²+12-12a +6a-12

=3a²-6a

=3a(a-2)

Answer 2

$\huge\tt\colorbox{white}{AnsweR}$

$\sf\:3(a - 2)² + 6(a-2)$

Using formula :

$\tt\purple{(a-b)^{2}=a^{2}-2ab+b^{2}}$

$\sf⟹\:3(a^{2} - 2 \times a \times 2 + 2^{2}) + 6a-12$

$\sf⟹\:3(a^{2} - 4a + 4) + 6a-12$

$\sf⟹\:3a^{2} - 12a + 12 + 6a-12$

$\sf⟹\:3a^{2} - 12a + 6a+12-12$

$\sf⟹\:3a^{2} - 6a +12-12$

$\sf⟹\:3a^{2} - 6a + 0$

$\sf⟹\:3a^{2} - 6a$

$\sf⟹\:3a(a - 2)$

$\sf\:Either\:3a=0$

$\sf⟹\:a=\frac{0}{3}$

$\tt\pink{⟹\:a=0}$

$\sf\:oR\:a-2=0$

$\tt\pink{⟹\:a=2}$

• Thnku ❣