Question

3/a - 2/b + 1/4 for a = -2, b = 3
please give me answer it is important.​

Answer 1

Step-by-step explanation:

-3/2-2/3+1/4

=-9-4/6+1/4

=-13/6+1/4

=-52+6/24

=-46/24= -23/12

Answer 2

Step-by-step explanation:

Given:

$\frac{3}{a} -\frac{2}{b} +\frac{1}{4}$ and $a=-2,b=3$

To find:

The value of the $\frac{3}{a} -\frac{2}{b} +\frac{1}{4}$ where $a=-2,b=3$.

Solution:

Given that $\frac{3}{a} -\frac{2}{b} +\frac{1}{4}$ and $a=-2,b=3.$

⇒$\frac{3}{a} -\frac{2}{b} +\frac{1}{4}$

Here $a=-2$ and $b=3,$

⇒ $\frac{3}{-2} -\frac{2}{3} +\frac{1}{4}$

The fraction $\frac{3}{-2}$ can be written as $-\frac{3}{2}$ by extracting the negative sign.

⇒ $-\frac{3}{2} -\frac{2}{3} +\frac{1}{4}$

The least common multiple of $2$ and $3$ is $6$. Convert $-\frac{3}{2}$ and $\frac{2}{3}$ to fractions with denominator $6.$

⇒ $-\frac{9}{6}- \frac{4}{6} +\frac{1}{4}$

⇒ $\frac{-9-4}{6} +\frac{1}{4}$

Subtract $4$ from $-9$ to get $-13$.

⇒ $\frac{-13}{6} +\frac{1}{4}$

The least common multiple of $6$ and $4$ is $12.$Convert $-\frac{13}{6}$ and  $\frac{1}{4}$ to fractions with denominator $12.$

⇒ $-\frac{26}{12} +\frac{3}{12}$

Since $-\frac{26}{12}$ and $\frac{3}{12}$ have the same denominator, add them by adding their numerators.

⇒ $\frac{-26+3}{12}$

⇒ $\frac{-23}{12}$

∴ The value of the $\frac{3}{a} -\frac{2}{b} +\frac{1}{4}$ where $a=-2,b=3$ is $\frac{-23}{12}$ or $-1.91666666.$

Answer:

Hence the answer is $\frac{-23}{12}$ or $-1.91666666.$