Question

3. A 20 litre container at 400 K contains CO2(g) at
pressure 0.4 atm and an excess of Sro (neglect
the volume of solid SrO). The volume of the
container is now decreased by moving the movable
piston fitted in the container. The maximum volume
of the container, when pressure of CO2 attains its
maximum value, will be :-​

Answer 1

Answer:

Explanation:

By using Ideal gas equation,

PV=nRT

⇒0.4atm×20L=n  

CO  

2

​  

 

​  

×R×400K

⇒n  

CO  

2

​  

 

​  

=  

R

0.2

​  

 mole ⇒ Initial moles of CO  

2

​  

 

After reaching the Equilibrium,

SrCO  

3

​  

(s)⇌SrO(s)+CO  

2

​  

(g)

All pressure will be because of CO  

2

​  

 only as it is the gaseous substance.

∴K  

P

​  

=P  

CO  

2

​  

 

​  

=1.6atm

P  

2

​  

V  

2

​  

=nRT

⇒1.6atm×V  

2

​  

=  

R

0.2

​  

×R×400

⇒V  

2

​  

=5L

Thus when the pressure of CO  

2

​  

 will be maximum i.e. 1.6atm the volume will be 5L .