Physics, asked by talhakhantk4646, 9 months ago

3. A 200V ideal AC source is connected to 100
resistor the power dissipated in 30 minutes is
a. 200 watt
b. 100 watt
c. 400 watt
d. 600 watt

Answers

Answered by ansa2000mol

1

Answer:

400 watt

Explanation:

P = VI OR V^2 /R

= 200^2 / 100

= 40000/100

= 400 watt

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