Question

3^(a)=27^(b+1) and 5^(b)=25^(a-1) find a+b​

Answer 1

Answer:

here it is: a+b

Answer 2

Step-by-step explanation:

Given 3^(a)=27^(b+1) and 5^(b)=25^(a-1) find a+b

• Given 3^a = 27^b + 1
•         3^a = 3^3 (b + 1)
•        3^a = 3^3b + 3  
• So a = 3b + 3 (bases are same so exponents are equal)
•   Also 5^b = 25^a – 1
•             5^b = 5^2 (a – 1)
•               5^b = 5^2a – 2
•    So b = 2a – 2
• Now a = 3b + 3
•    So a = 3(2a – 2) + 3
•    So a = 6a – 6 + 3
•  Now – 5a = - 3
• Or a = 3/5
• Now b = 2a – 2
•             = 2(3/5) – 2
• Or b = - 4/5
• So a + b = 3/5 + (-4/5)
•                  = 3/5 – 4/5
•                       = - 1/5

Reference link will be

https://brainly.in/question/14671656