3^a=27^b+1 and 5^b=25^a-1 , then a+b =
Answers
value of a + b = 1/5
It is given that, 3^a = 27^(b + 1) and 5^b = 25^(a - 1)
and we have to find a + b
3^a = 27^(b + 1)
⇒3^a = (3³)^(b + 1)
⇒3^a = 3^(3 × (b + 1))
⇒3^a = 3^(3b + 3)
⇒a = 3b + 3 .........(1)
again, 5^b = 25^(a - 1)
⇒5^b = 5^{2(a - 1)}
⇒5^b = 5^(2a - 2)
⇒b = 2a - 2 ..........(2)
from equations (1) and (2) we get,
a = 3(2a - 2) + 3
⇒a = 6a - 6 + 3
⇒-5a = -3
⇒a = 3/5
and b = 2 × 3/5 - 2 = -4/5
hence, a + b = 3/5 - 4/5 = 1/5
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The value of a + b is -1/5
- Given,
- Bases are same, equate the powers.
a = 3b + 3 ----------------(1)
- Also,
- Bases are same, equate the powers.
b = 2a - 2
b = 2(3b + 3) -2 [from (1)]
b = 6b + 6 -2
b - 6b = 4
-5b = 4
b = -4/5
- Substituting 'b' in (1)
a = 3(-4/5) + 3
5a = -12 + 15
5a = 3
a = 3/5
- Now,
a + b = 3/5 - 4/5
a + b = -1/5