3(a-2b) ²-5(a-2b) factorise
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0
Answer:
3
(
−
2
)
2
−
5
(
−
2
)
3\left(a-2b\right)^{2}-5(a-2b)
3(a−2b)2−5(a−2b)
3
(
−
2
)
(
−
2
)
−
5
(
−
2
)
Answered by
0
Answer:
By taking (a-2b) as a common factor for the above equation we get, 3(a-2b) 2 – 5(a-2b) = (a-2b) (3(a-2b) – 5) = (a-2b) (3a -6b -5)
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