Math, asked by pagal1889, 7 months ago

3(a-2b)^2 - 8a + 16b + 4

Answers

Answered by nihitKaranjwala
0

Step-by-step explanation:

3(a-2b)^2-8a+16b+4

3(a-2b)^2-8(a-2b)+4

let (a-2b) be x

3x^2-8x+4

3x^2-2x-6x+4

x(3x-2)-2(3x-2)

(x-2)(3x-2)

Substitute the value

(x-2)(3x-2)

(a-2b-2)[3(a-2b)-2]

(a-2b-2)(3a-6b-2)

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