Question

3. A 4 kg stone tied at the end of a 1 m long string is whirled
in a vertical circle. At the instant when the string makes
an angle theta with the vertical, the linear speed of the stone
is 4 m/s and the tension in the string is 103.2 N. Then
the value of theta is
​

Answer 1

Explanation:

T=m[g cos theta + v^2/r]

103.2=4[9.8 cos theta + 16/1]

25.8= 9.8 cos theta + 16

cos theta =9.8/9.8= 1

theta= 0 degree.