Question

3. (a) ABCD in which AB = 8 cm, BC = 6 cm, CD = 4 cm, AD=5 cm and ⟨B=60degree
(b) PQRS in which PQ = QR = 4.5 cm, PS = RS = 5.8 cm, PQR = 120°.
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Answer 1

Answer:

AB =8

BC=6

CD=4

AD=5

∆B= 60°

ANSWER

AB+BC+CD+AD=∆B

8+6+4+5=60

23=60

23÷60

PQ=QR=4.5

PS=RS=5.8

PQR=120°

PQ+QR+RS+PS =PQR

4.5+4.5+5.8+5.8=120°

9+11.06 =120°

20.06=120°

20.06÷120°

23×60÷20.06×120

1380÷2407.2

0.573