Question

3)
.
A & B are mid points of 2 equal
chords P Q & RS
a circle with centre as shown in the figure
Prove that:
1) angle oab= angle oba
1) angle qab =angle rba

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Answer 1

Answer:

Answer with Step-by-step explanation:

A and B are mid point of equal chords PQ and RS.

PQ=RSPQ=RS

\frac{1}{2}PQ=\frac{1}{2}RS21PQ=21RS

AQ=BSAQ=BS

In triangle OAQ and OBS

OA=OBOA=OB (Equal chords are at equal distance from center)

OQ=OSOQ=OS (Radius of circle)

AQ=BSAQ=BS

\triangle△ OAQ\cong\triangle≅△ OBS