Math, asked by pihu15125, 6 months ago

3, a and 11 are three consecutive terms of an A.P. Value of a is:

Answers

Answered by Anonymous

1

Answer:

a = 7

Step-by-step explanation:

t1 = 3

t2 = a

t3 = 11

Common difference is d.

d = a - 3 ----> eq 1.

d = 11 - a -----> eq 2.

Substitute eq 1 in eq 2,

a - 3 = 11 - a

a + a = 11 + 3

2a = 14

a = 14 / 2

a = 7

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