Question

3) A and B, working together can finish a piece of work in 6 days, while A alone can do it in
9 days. How much time will B alone take to finish it?​

Answer 1

Step-by-step explanation:

18 days

Step-by-step explanation:

Since, a alone do the work in 9 days,

So, the one day work of A = \frac{1}{9}

9

1

Also, both a and b do the work in 6 days,

⇒ The combined one day work of a and b = \frac{1}{6}

6

1

Thus, the one day work of b = The one day work of both a and b - One day work of a

=\frac{1}{6}-\frac{1}{9}=

6

1

−

9

1

=\frac{3-2}{18}=

18

3−2

=\frac{1}{18}=

18

1

Hence, the time taken by b alone = \frac{1}{\text{ His one day work}}

His one day work

1

=\frac{1}{1/18}=

1/18

1

=18\text{ days}=18 days