3 a/b a value a value =6 and b value =3
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Answers
Answered by
0
Answer:
Step-by-step explanation:
We know that,
A×B=ABsinθ
Also, A.B=ABcosθ
Given : ∣A×B∣=
3
A.B
Using ∣A×B∣=∣A∣∣B∣sinθ
We get ∣A×B∣=ABsinθ
A.B=∣A∣∣B∣cosθ
∴ ABsinθ=
3
ABcosθ
tanθ=
3
⟹θ=60
o
Now (A+B)
2
=A
2
+B
2
+2A.B
=A
2
+B
2
+2ABcosθ
=A
2
+B
2
+2AB×
2
1
=A
2
+B
2
+AB
or ∣A+B∣=(A
2
+B
2
+AB)
1/2
Answered by
0
Answer:
Case 1: A is not equal to 0
Assuming [matha≠0[/math],
A+A+A=BA
Combining the A’s on the left side, we get:
3A=BA
Dividing both sides by A, we arrive at:
B=3
A can be any number it wants to be in this case.
Case 2: A is equal to 0
In this case, our equation simplifies to:
0=0∗B
We get A=0 and B can be any number.
Recap: Either B=3 and A can by anything, or B can be anything and A=0
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