Question

3. A bag contains 4 red, 5 black and 3
yellow balls.A ball is taken out of the
bag at random.Find the probability
that the ball taken out is of yellow
colour.
O 1/2
O 1/3
O 1/4
O 1/5​

Answer 1

Answer:

1/4

Step-by-step explanation:

total balls = 5+4+3

yellow balls=3

probability of getting a yellow ball= 3÷12

=1/4

Answer 2

Answer:

$No. \: of \: favourable \: outcomes=3 \\ </p><p>Total \: no. \: of \: outcomes=4+5+3=12 \\ </p><p>P(yellow \: ball)= \frac{No. \: of \: favourable \: outcomes}{Total \: no. \: of \: outcomes} = \frac{3}{12} = \frac{1}{4} \\ Therefore, \: the \: probability \: that \: the \: ball \: taken \: out \: is \: of \: yellow \: colour \: is \frac{1}{4} . \\ Option \: C$