Question

3. A bag contains 6 red balls and 4 blue balls. A ball is drawn from the bag without
looking into the bag? What is the probability of drawing a red ball? Is it more o
less than getting a blue ball?​

Answer 1

Answer:

No. of red balls =n(R)=6

Let, no. of blue balls be x, n(B)=x

Total no. of balls in bag=n(T)=6+x

We know that, Probability P(Event) =(Total no.of possible outcomes)(No.of favorable outcomes)

Probability of drawing a red ball, P(R)=6+xn(R)

Probability of drawing a blue ball, P(B)=6+xn(B)

Given,

Probability of drawing a blue ball from the bag is twice that of a red ball

i.e., P(B)=2×P(R)

6+xn(B)=2×6+xn(R)

x=2×6

n(B)=x=12

Total no. of balls in bag=n(T)=6+x=6+12=18.