3. A ball dropped from roof. This motion is
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Answered by
0
Answer:
Explanation:
A ball is dropped from the roof of a tower height =h
Total distance covered it in the last seconds of its motion
Solution
The distance covered in first 3 second
s=
2
1
at
2
=
2
1
×10×3
2
=45
If the ball takes in second to fall to ground. The distance covered in nth second
s
n
=u+
2
g
(2n−1)
=0+
2
10
(2×n−1)
=10n−5
Therefore, 45=10n−5
10n=50
n=5
Thereforeh=
2
1
=
2
1
gt
2
=
2
1
×10×25
=125m
Answered by
0
Answer:
Non uniform. When the ball is dropped from the top of the building, its initial velocity will be zero, and will keep on increasing every second by magnitude of 9.81 by virtue of the acceleration due to gravity
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