Question

3. A ball is dropped from the top of a tower. The
distance covered in the last one second is 0.36
times the height of the tower. What is the
height of the tower ? (g = 10 m/s2)


3. एक गेंद को एक टॉवर के ऊपर से गिराया जाता है।
अंतिम एक सेकंड में तय की गई दूरी 0.36 है
टॉवर की ऊंचाई से कई गुना। क्या है
टॉवर की ऊंचाई? (जी = १० मीटर / एस २)
​

Answer 1

Answer:

A ball is dropped from the roof of a tower height =h

Total distance covered it in the last seconds of its motion

Solution

The distance covered in first 3 second

s=

2

1

at

2

=

2

1

×10×3

2

=45

If the ball takes in second to fall to ground. The distance covered in nth second

s

n

=u+

2

g

(2n−1)

=0+

2

10

(2×n−1)

=10n−5

Therefore, 45=10n−5

10n=50

n=5

Thereforeh=

2

1

=

2

1

gt

2

=

2

1

×10×25

=125m

Explanation:

I hope it is helpful for you