Question

3. A ball is thrown vertically upwards. It returns
6 s later. Calculate : (i) the greatest height reached
by the ball, and (ii) the initial velocity of the ball.
(Take g = 10 m 52 Ans. (i) 45 m, (ii) 30 m s-1
​

Answer 1

Explanation:

time of ascent /descent = 3 s

1. s = ut - ½ at²

- H = 0 - ½ x 10 x 9

H = 45 m

2. v² - u²= -2as

0 - u² = - 2 x 10 x 45

u = 2x 5 x 3 = 30m/s