3. A ball of mass 100g moving with a velocity of Om/s is stopped by a boy in 0.2s. Calculate the force
applied by the boy to stop the ball.
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Ans - Initial velocity of ball u=−10 m/sInitial momentum P i =mu=0.1×(−10)=−1 kg m/sFinal velocity of ball v=10 m/sFinal momentum P f =mv=0.1×10=1 kg m/sTime of action t=0.01 sUsing F×t=P f −P i Or F×0.01=1−(−1)=2⟹ F=200 N
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