Question

3. A battery of 10 volt carries 20,000 C of charge through a resistance of 20 n.
The work done in 10 seconds is​

Answer 1

Answer:

v = 10

R=20

we know that

V=I/R

10=I/20

I=10x20

I=200

in 1 sec =200

In 10 sec=200x10

=2000

Answer 2

Answer:

Anser is 200 Kj.

Step-by-step explanation:

Given: V = 10V

Q = 20000C

R = 20 ohm

Current= Charge/time

= 2000A

Work done: V.I.T

=10×2000×10

=200000J

=200Kj