Question

3 A block of mass 2 kg has dimensions 5cm 20cm x 10cm, The ratio of minimum tomaximum pressure exerted on the change in Orientation is -
a)1:1
b) 1:2
c) 1:4
d) 4:1​

Answer 1

Answer:

Pressure is the force per unit area. So, P=F/A

Thus, minimum surface area (5cm×10cm) will give the maximum pressure and maximum area (20cm×10cm) will give the minimum pressure.

So, P

max

​

=

50×10

−4

2g

​

N/m

2

and P

min

​

=

200×10

−4

2g

​

N/m

2

Thus,

P

max

P

min

​

=50/200=1/4

The option C will be right.

Answer 2

Answer:

1:1 correct answer please mark me brainlest and follow me