3.A body is dropped freely under gravity from the top of a tower of height 78.4m. Calculate i] the time to reach the ground and ii] the velocity with which it strikes the ground. [Take g=9.8m/s²]
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Calculate i] the time to reach the ground and ii] the velocity with which it strikes the ground.
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Answer:
Explanation:
h=1/2gt²
=> 78.4=1/2×9.8×t²
=> 78.4= 4.9t²
=> t²=78.4/4.9
=> t²=16
=> t=√16
=> t=4
Hence, time is 4 seconds.
Velocity at which it strikes the ground is v=u+gt
u=0
g=9.8m/s²
t= 4 seconds m/s
=> v= 9.8×4
=> v= 39.2 m/s (Answer)
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