Question

3. A body is pivated at a point. A force of 10 N is applied at a distance of
30 cm from the pivot. Calculate the moment of force about the pivot

Answer 1

Answer:

3 Nm

Explanation:

Moment of force is calculated as:

Force x (perpendicular distance between point of application of force and axis of rotation)

But the unit should of the same system, SI or CGS

Here, Force = 10 N

     Distance = 30/100 = 0.3 m

Hence, Moment of force = 10x0.3 Nm

                                         = 3 Nm

Answer 2

Answer:

3 N m

Explanation:

given,

F = 10 N , r = 30 cm = 0.3 m

Moment of force = F*r  =  10 * 0.3 = 3 N m