Question

3. A body is thrown vertically upwards and takes
5 seconds to reach maximum height. The distance
travelled by the body will be same in
(1) 1" and 10 second (2) 2nd and 8 second
(3) 4th and 6th second (4) Both (2) & (3)​

Answer 1

Dear student

1st and 10th second is correct answer.

using g = 10 m/sec^2 :

Vo = g*t = 10*5 = 50 m/sec

from t = 0 to t = 1 sec

h = ((Vo*1-5*1^2)-0) = (50-5) = 45 m (up)

from t = 9 to t = 10 sec

h = ((Vo*10-5*10^2)-(Vo*9-5*9^2)

h= (0-450+405) = -45 m (down