Question

3. A body moving with uniform acceleration covers the distance between
two points 60 m apart in 6 sec. Its velocity as it passes the first point is 5
ms. (a) What is its acceleration ? (b) What is the velocity at the second
point?​

Answer 1

Step-by-step explanation:

Distance=60m

Time=6s

Velocity=5m/s

Acceleration=

$\frac{v}{t }$

$= \frac{5}{6} \frac{m}{ {s}^{2} }$

Velocity=

$\frac{s}{t}$

$= \frac{60}{6} = 10 \frac{m}{s}$

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Answer 2

Answer:

Distance=60m

Time=6s

Velocity=5m/s

Step-by-step explanation: