Question

3.) A body of mass 5 kg displaces 1000cm3 of water when fully immersed in water. find:
(1) volume of the body (2)apparent weight of
the body in water.​

Answer 1

A body of mass 5kg displaces 1000 cm³ of water when fully immersed in water.

To find : (1) volume of the body

(2) apparent weight of the body in water.

solution : according to Archimedes principle,

(1) volume of water displaced by the body = volume of the body.

here volume of water displaced by the body is 1000 cm³

so, volume of the body = 1000 cm³ = 1000 × (10¯² m)³

= 10¯³ m³

(2) apparent weight = true weight - upthrust

first we have to find upthrust.

upthrust = volume of water displaced by the body × density of water × g

= 10¯³ m³ × 10³ kg/m³ × 10 m/s²

= 10 N

now apparent weight = 5kg × 10 m/s² - 10 N

= 50 N - 10 N

= 40 N

Therefore apparent weight of the body in water is 40 N

Answer 2

Answer:

Explanation:

A body of mass 5kg displaces 1000 cm³ of water when fully immersed in water.

To find : (1) volume of the body

(2) apparent weight of the body in water.

solution : according to Archimedes principle,

(1) volume of water displaced by the body = volume of the body.

here volume of water displaced by the body is 1000 cm³

so, volume of the body = 1000 cm³ = 1000 × (10¯² m)³

= 10¯³ m³

(2) apparent weight = true weight - upthrust

first we have to find upthrust.

upthrust = volume of water displaced by the body × density of water × g

= 10¯³ m³ × 10³ kg/m³ × 10 m/s²

= 10 N

now apparent weight = 5kg × 10 m/s² - 10 N

= 50 N - 10 N

= 40 N

Therefore apparent weight of the body in water is 40 N