Question

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3. A body of mass 5 kg moves under a force of 10 i +15j+20 k.
What is the deceleration produced ? [Ans : 21 +3j +4k] how this answer came????​

Answer 1

Answer:

2i+3j+4k

Explanation:

We know, F= m.a, where F and a are vector quantities.

So a= F/m, since m=5kg is a scalar, we need not worry and can simple divide each vector term by the scalar.

so, a= (10i+15j+20k)/5

This implies, a= (10/5)i+(15/5)j+(20/5)k

a= 2i+3j+4k

however the question says deceleration but in this case there is no deceleration and it's simply acceleration.

Answer 2

Correct Question:-

A body of mass 5 kg moves under a force of 10i+15j+20 k. What is the deceleration produced ?

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Answer:-

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Given:

▪︎Mass = 5 kg

▪︎Force = 10i + 15j + 20k

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To Find:

▪︎Acceleration of object

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Solution:

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As we know,

$\boxed{\pink{\bf{Force = Mass × Acceleration/decelaration}}}$

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Putting the given values in equation,

${\sf{10i + 15j + 20k = 5 × decelaration}}$

${\sf{\implies 10i + 15j + 20k ÷ 5 = declaration}}$

${\sf{\implies decelaration = 2i + 3j +4k}}$

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$\Large\boxed{\blue{\sf{\therefore decelaration = 2i + 3j + 4k}}}$

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Verifying:

Putting each value in equation;

Force = Mass × Decelaration

${\sf{\implies 10i + 15j + 20k = 5 × 2i+3j+4k}}$

${\sf{\implies 10i + 15j + 20k =10i + 15j + 20k}}$

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${\sf{\therefore L.H.S = R.H.S}}$

Hence, verified that above answer is correct.