Question

3. A body of mass 6 kg is moving with a velocity of 2 m/s. Calculate the force required to stop in
5 s. How far it will travel before coming to rest.
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Answer 1

Answer:

It is given that :-

•Mass of body = 6kg

•Initial velocity = 0

•Final velocity = 2m/s

•Time = ?

•Force required to stop = ?

Acceleration of this body = v /t = 2/5 = 0.4

Now the force required to stop body will be :

f=ma

f=6×0.4=2.4n

Therefore 2.4N force is required to stop body.

Now according to third equation of motion, square of final velocity of body is equals to sum of its initial velocity and double of product of acceleration and distance. Represented by :-

V²=u²+2as

S=V²-U²/2a

After inputting the values we get :-

S=2²-0²/0.4×2

=S=4/0.8

=5

Therefore it travels 5m while getting stopped.

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Explanation:

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