3.A body of weight 500g in air 300gm in water. a)Find the loss of weight of the object in water.(2) b)Find out the buoyancy force exerted by water on the body (1)
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Weight of the body in air =500gf
Weight of the body in water =450gf
∴ (i) loss of weight of the body when immersed in water =500gf−450gf=50gf.
(ii) upthrust of the body=loss in weight of the body =50gf.
(iii) upthrust =Vdg
⇒50gf×g=V×1gcm
−3
×g(densityofwater=1gcm
−3
)
⇒volumeofthebodyV=50cm
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