Question

(3) A body starts from rest with a uniform acceleration 2m/s? Find
the distance covered by the body in 2 seconds.
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Answer 1

Answer:

4 meter

Explanation:

u=0, a=2m/s, t=2s

S = ut + (1/2)at²

= 0 + (1/2) × 2 × 2²

= 2²

= 4m

Answer 2

Given :

• Body starts from Rest so, initial velocity, u = 0
• Acceleration of body, a = 2 m/s^2
• Time for travelling, t = 2 sec

To find :

• Distance covered by the body in 2 seconds, s = ?

Formula required :

• Second equation of motion

s = u t + 1/2 a t^2

[ where s is distance covered, u is initial velocity, t is time and a is acceleration ]

Calculation :

Using second equation of motion

➥ s = u t + 1/2 a t^2

➥ s = (0) (2) + 1/2 (2) (2)^2

➥ s = 4 m

therefore,

• Distance covered by Body will be 4 metres.

Three equation of motion :

• First eqaution of motion :

v = u + a t

• Second equation of motion :

s = u t + 1/2 a t^2

• Third eqaution of motion :

2 a s = v^2 - u^2

[ where v is final velocity, u is initial velocity, a is acceleration, t is time, s is distance covered ]