Question

3. A body starts with an initial velocity of 20 m s-1 and acceleration 5 ms-2 Find the distance
covered by it in 5 s.
.

Answer 1

Answer:

Distance covered = 162.5 m

Step-by-step explanation:

Given:

Initial velocity (u) = 20 m/s

Acceleration (a) = 5 m/s²

Time (t) = 5 secs

Equation of motion:

Distance (s) = ut + $\frac{at^2}{2}$

                   = 20 × 5 + $\frac{5*5^2}{2}$

                   = 100 + 62.5

                   = 162.5 m

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