Question

3. A body travels through a distance of 10 m on a straight
line, under the influence of 5 N. If the work done by the
force is 25 J, the angle between the force and displace-
ment is:
(A) 0°
(B) 30°
(C) 60°
(D) 90°

Answer 1

Answer:(c) 60º

Explanation:

since,W=FSCOSθ

Therefore,25=5⨯10⨯cosθ

25=50cosθ

Here,θ must be 60º for the above equation to be true

Answer 2

Answer:

60°

Explanation:

work done=f.s×costhita

25 =5×10×costhita

25×1/50 = costhita

value of costhita is 60°.

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