Question

3. A bowler throws a ball of mass 125 gm with a velocity
of 90 km hr-1 to a batsman. Calculate the kinetic
energy of the ball.
[Ans. 39.06 J]​

Answer 1

Answer:

[Ans. 6561 J].

Explanation:

$k.e = \frac{1}{2} mv {}^{2} \\ k.e = \frac{1}{2} \times 0.125 \times (324) {}^{2} \\ k.e = \frac{1}{2} \times 0.0625 \times 104976. \\ k.e = 6561joule... \\ hope \: its \: helps....$

Answer 2

Answer:

39.0625 Joule

Explanation:

m = 125g = 0.125kg

v = 90km/hr = 90000m/3600s = 25m/s

KE = 1/2mv² = 1/2×0.125kg×25²m/s = 39.0625 Joule