3. A box contains 21 balls
numbered 1 to 21. A ball is drawn
and then another ball is drawn
without replacement. What is the
probability that both balls are even
numbered?
(10/16)
(3/14)
(10/14)
(3/16)
Answers
Answered by
0
Answer:
10/16
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Answered by
0
Answer:
3/14
Step-by-step explanation:
P(B/A)×P(A)
(9/20)×(10/21)
3/14
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