3. A box contains 3 red balls, 7 black balls and 5 green balls. one ball is drawn from the box at random. Find the probability of drawing a:
(a) green ball
(b) black or red ball (c) ball that is not black
Answers
Answered by
7
Total number of balls=3+7+5
=15
therefore,green balls=5/15
=1/3
black ball=7/15
red ball=3/15
=1/5
ball that is not black=3+5/15
=8/15
Hope it helps you ☺️
mark me as a brainlist ❤️
Similar questions