3. A box contains 4 choco-bars and 4 ice creams. Tom eats 3 of them, by randomly choosing. What is the probability of choosing 2 choco-bars and 1 ice cream?
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Answer:
No. of. choco -bars =4
No. of. ice creams=4
=8
p(E)=No of favorable outcomes/
No of total outcomes
probability of getting 2 choco-bars and
1 ice cream:
Tom eats 3 of them so,
8-3=5
P(2 choco-bars and 1 ice cream)=5/8
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