Question

3. A brass rod at 30°C is observed to be Im long when measured by a steel
scale which is correct at 0°С. Find the corrected length of the rod at O'C
Given a for steel is 1.2 x 10°C and a for brass is 1.9 X 10^-5 ⁰C^-1​

Answer 1

Answer:

As steel scale is correct at 0℃.

Actual length measured by steel scale at 30℃.

L=100(1+t×α)

L=100(1+12×10

−6

×30)

L=100(1.00036)cm

L=100.036cm

Brass rod has length 100.036cm at 30℃ let's assume length L' is length at 0℃

so -

100.036=L

′

(1+t×α)

100.036=L

′

(1+19×10

−6

×30)

100.036=L

′

(1.00057)

L

′

=99.979cm

Answer 2

Answer:

thanks for free point good Night