Question

3. A bullet of mass 20g moving with a velocity of 300m/
embedded in a freely sudpended block of 880g, what is
the velocity of
the block?​

Answer 1

Given:

▪ Mass of bullet = 20g

▪ Mass of block = 880g

▪ Initial velocity of bullet = 300m/s

To Find:

▪ Velocity of system (block + bullet) after collision.

Calculation:

$\sf\ ⇉Pi = Pf$

$\sf\ ⇉(m×v)+(M×V)=(M+m)V$

$\sf\ ⇉(0.02×300)+(0.88×0)=(0.02+0.88)V$

$\sf\ ⇉ 6+0=0.9V$

$\dashrightarrow\: \underline{\boxed{\bf{\red{ V=6.67mps}}}}$

$\rule{160}3$

$\large\underline\bold{Additional\: Information}$

• Conservation of momentum states that the momentum of the body remains conserved if no external force is applied on it.
• Velocity is the rate of change of the position of an object. Mathematically it is division of displacement by time.It is a vector quantity. Its S.I. unit is m/s.

$\rule{160}3$