Question

3. A bullet, of mass 50 g strikes a wooden plank with a velocity of
by the bullet against the resistive force offered by the plank.
and emerges out with a velocity of 50 ms -- Calculate the work done​

Answer 1

Answer:

Work done = -937.5J

Explanation:

Total work done = loss in kinetic energy

Initial velocity = $v_i$ = 200m/s

Final velocity = $v_f$ = 50m/s

Total work done =

$\frac{1}{2}mv_{f}^{2} - \frac{1}{2}mv_{i}^{2}\\\\\frac{1}{2}m(v_{f}^{2} - v_{i}^{2})\\\\\frac{1}{2}(0.05)((50)^{2} - (200)^{2})\\\\\frac{1}{2}(0.05)(50+200)(50-200)\\\\\frac{1}{2}(0.05)(250)(-150)\\\\-937.5J$

Work done = -937.5J

Might Help!! Thanks!!