3. A bullet of
of mass 5g moving with a
velocity of 200m/s gets embedded in a freely suspended wooden block of mass 1000g. The velocity acquired by the block will be ________
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Explanation:
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Initially only the bullet is moving with velocity 200m/s ,later the block and velocity move with some velocity v which can be found from conservation law of momentum:
0.05×200+5×0=(5.05)×v
10=5.05v
v=
5.05
10
=1.98m/s
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