3. A bus increase its speed from 36 km/h to 72km/h in 10 second. Its
acceleration is (MARK-1)
a, 2m/s2
b. 1m/s2
c. 3.6m/s2
d.5m/s?
Answers
Answered by
7
Answer:
1m/second²
Solution:
acceleration = Rate of change of Velocity.
initial velocity- 36km/h
final Velocity-72km/h
convert it into m/s
initial velocity- 10m/s
final velocity-20m/s
Acceleration- V-u/T
→ Acceleration = 20-10/10
→ 1m/s²
Answered by
0
Answer:
b.1m/s2
Explanation:
Initial velocity = u = 36 km/hr = 10 m/s.
Final Velocity = v = 72 km/hr = 20 m/s
Time = t = 10 seconds.
Therefore,
acceleration = a = v-u/t
= (20-10/10) m/s^2
= (10/10) m/s^2
=1 m/s^2. [Ans]
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