Question

3)A bus slows with constant acceleration from 24 m/s to 16 m/s and moves 50 m in the process. (a) How much farther does it travel before coming to a stop? (b) How long does it take
to stop from 24 m/s?

Answer 1

Answer:

(a) 40 m

(b) 7.5 sec

Explanation:

At first I've calculated the acceleration of the bus using

v^2 = u^2 - 2as formula.

Then using the same formula I've calculated the anwer a and the second one is calculated using v=u - at.