Question

3. A bus starts from the stop and take 50 seconds to get the speed of 10 m/s. If
the mass of the bus along with passengers is 10000 kg, calculate the force
applied by the engine of bus to push the bus at the speed of 10 m/s.

Answer 1

Given :

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 10 m/s
• Time interval (t) = 50 seconds
• Mass (m) = 10000 kg

To Find :

• Force applied by engine on train to push at speed of 10 m/s

Solution :

For calculating the force applied by the engine, we've to find out the value of acceleration of the engine.

Use 1st equation of motion :

⇒v = u + at

⇒v - u = at

⇒a = (v - u)/t

⇒a = (10 - 0)/50

⇒a = 10/50

⇒a = 1/5

⇒a = 0.2

$\therefore$ Acceleration is 0.2 m/s²

________________________________

Now, use formula for force :

⇒F = ma

⇒F = 10000 * 0.2

⇒F = 2*1000

⇒F = 2000

$\therefore$ Force applied by engine on train is 2000 N

Answer 2

Answer:

Given :

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time interval (t) = 50 seconds

Mass (m) = 10000 kg

To Find :

Force applied by engine on train to push at speed of 10 m/s

Solution :

For calculating the force applied by the engine, we've to find out the value of acceleration of the engine.

Use 1st equation of motion :

⇒v = u + at

⇒v - u = at

⇒a = (v - u)/t

⇒a = (10 - 0)/50

⇒a = 10/50

⇒a = 1/5

⇒a = 0.2

Acceleration is 0.2 m/s²

________________________________

Now, use formula for force :

⇒F = ma

⇒F = 10000 * 0.2

⇒F = 2*1000

⇒F = 2000

Force applied by engine on train is 2000 N

Explanation: