3. A canal is 300 cm wide and 120 cm deep. The water in the canal is flowing with a speed of 20km/h. How much area will it irrigate in 20 minutes if 8 cm of standing water is desired?
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Answer:
required area=300000 m²
Step-by-step explanation:
1m=100cm
∴1cm=1/100m
width of canal =300cm =300/100m =3m
depth of canal = 120cm =120/100m = 1.2m
volume of water that flows in canal in one hour=width of canal×depth of canal×speed of canal water
=3×1.2×20×1000m³
=72000m³
the volume of water in canal in 20 minutes=72000×20/60m³
=24000m³
area irrigated in 20 minutes,if 8cm waater is required(8cm=0.08m)
24000/0.08m²
=300000m²
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