Question

3.A car accelerates uniformly from 10 km/hr

to 40km/hr in 4seconds.

Calculate (i) Acceleration

(ii) distance travelled by the car

in this time​

Answer 1

Answer:

vi=10km/h = 10×1000/3600=2.77m/s

vf=40km/h= 40×1000/3600= 11.11m/s

a=?, distance=?

since vf=vi+at

11.11=2.77+a(4)

11.11-2.77=4a

8.34=4a

a=8.34/4

a=2.08m/s^2

now for distance (S)

2aS=vf^2-vi^2

2(2.08)S= 11.11^2-2.77^2

4.16S=123.43-7.67

4.16S=115.757

S=115.757/4.16

S=27.82m