3.A car acquires a velocity of 36 km per hour in 10 minutes starting from rest.Find (i) the acceleration, (ii) the average velocity, and (iii) the distance travelled inthis time.
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Answer:
Initial velocity (u) = 0
Final velocity (v) = 36km/h = 36×5/18 = 10m/s
Time = 10min = 10×60 = 600sec
Accleration = v-u/t
a = 10 - 0/600
a = 0.01667m/s^2 Average velocity = u+v/2 =0+10/2 m/s = 5 m/s (or) 3000/600 = 5m/s
Applying formula v^2-u^2=2as
10^2 - 0^2 =2×0.01667s
0 - 100 = 0.03334
S = 3000m
S = 3Km.
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