Question

3. A car at rest starts moving with linear uniformly increasing velocity. After 20 seconds it attains the maximum
velocity of 80 m/s. What is the distance covered during this time interval?
A. 200m
B. 400m
C. 800m
D. 1600m​

Answer 1

Answer:

u=0m/s

v=80m/s

t= 20s

Explanation:

Let the distance be s

Thus,

V^2 - U^2 = 2as

6400=2*40*s

6400= 80s

s=6400/80

S=80 metre

Answer 2

Answer:

A car covered 800m during this time interval

Explanation:

u= 0m/s , v= 80m/s , t= 20m , a=? , s= ?

1st we find a

a = v-u/t

a = 80-0/20

a = 4m/s²

then we find distance (s)

v²-u² = 2as

=> 80² - 0² = 2(4)s

=> 6400 = 8s

=> s = 800m