Question

3. A car falls of a ledge and drops to the ground in 0.5 s. Let g= 10 ms-2
a. What is its speed on touching the ground?
b. What is its average speed during 0.5s?
c. How high is the ledge from the ground?

Answer 1

Answer:

solved

Explanation:

a. What is its speed on touching the ground? , v = gt = 0.5 s.x 10 ms-2 = 5m/s

b. What is its average speed during 0.5s?  , Vav = 5/2 = 2.5m/s

c. How high is the ledge from the ground? , H = v²/2g = 25/20 = 1.25 m.

Answer 2

a) v = 5 m/s

b) Vavg = 2.5 m/s

c) h = 1.25 m

Refer the attachments